1 Club

lid van

conform

Answers - undisturbed

 

The partner has one "weak" (conventional) answer : 1♦ , 0-7hp, all distributions. See below for the rebids of the opener.

 

All other answers are also conventional but GF and reveal a specific hand configuration. The hand types with highest probabilties come with the lowest bids.

 

1 Club from 16hp or 32zp onwards, all distributions

Hand type

Probability

8-24hp

%

0-7hp

54xx

17,6

 

4432

15,28

 

5332

11

 

4333

7,45

 

64xx

4,35

 

6322

4

 

55xx

2,9

 

6331

2,48

 

4441

2,13

 

65xx

1

 

73xx

1,56

 

74xx

0,55

 

7222

0,37

 

8+xxx

0,5

 

total

71,2

28,6

 

P

meaning : all 8+hp , MF

O : JNB, asking 1st time

O: JNB,asking 2nd time

1

54xx / 64+xx / 6331 w/ a M as longest suit

id M

id 2nd suit

1♠

54xx / 64+xx / 6331 w/ a m as longest suit

id m

id 2nd suit

1NT

5332 8+hp

id 5card

id doubleton

2

no 5 card

#cards in RSC suit * (s1234) or

(s5) $

#cards in next RSC suit

2

6322 w/ a M as longest suit

id M

id 3card

2♥

6322 w/ a m as longest suit

id m

id 3card

2♠

55xx w/ 5c♠

id 2nd suit

 

2NT

55xx w/o 5c♠ (♥♦/♥♣/♦ ♣)

2 suit combination

 

3x

7c in x, 7+hp

 

 

GEELSE BRIDGE CLUB

 

lokaal Geels Brouwhuis

Nieuwstraat 41, 2440 Geel 047 0710214

elke dinsdagavond om 19.30u stipt een open bridgetornooi

Standard Questions

 

The opener tries to find out the distribution and strength of his partner. He got already a first idea about the distribution via the answer on the opening.We agree upon a vast, standard set of questions in order to interprete the answers that come in as steps :

 

After a 54xxx/64xx/6331 hand : 1) id of longest suit ? 2)id of 2nd suit ?* 3) sn ? 4) strength ?

After a 5332 hand : 1) id of 5card ? 2) id of doubleton 3) strength ?

After a no 5 card hand : 1) amount of cards in a given suit 2) amount of cards in the next suit 3)strength ?

After a 6322 hand : : 1) id of longest suit ? 2)id of 2nd suit ? 3) strength ?

After a 55xx hand : 1) which combination ? 2) strength ?

Answering the asking bids via steps

 

In the neosqueeze system, the opener asks details about partners hand (distribution, strenght) with a Just Next Bid (JNB) in order to save bidding space. The answers are given in steps (s1=JNB, s2=JNB+1, s3=JNB+2 etc). In order to know what a certain step means, we agreed upon a reference sequence. JNB (just next bid) can be pass, JNB+1 can be (re)double when opponents overcall.

 

  • To identify a suit , the reference is the hierchical order of the suits : ♠ ♥ ♦ ♣ (eg. step 3 = ). If a 2nd suit of the same hand is asked, then the steps refer to the remaining suits. We name this method RSC, Relative Suit Code.
  • To identify a number of cards of a given suit; the reference sequence is '2341' the first time. If the number of cards is asked for another suit of the same hand, '4321' is the reference when the first answer was 4, the reference is '432' when the first answer was 2 or 3.
  • To identify the strength of a hand, the reference sequence is 8-10,11-12, 13-14, 15-16, etc
  • The lower the first answer revealing the handtype, the more information can be asked
  • The information asked is given in a defined order via the JNB. The opener can leave this order and directly ask for the strength by asking via JNB + 1
  • Never an openers asking bid is 3NT or higher, allowing a modest partner with 8-10 hp to answer his strength at the maximum with 3NT
  • The table below shows the monologue of partner P, telling first his handtype and next answering the predefined questions of opener O.
  • ! The 'extension technique' is always active where possible. See below.
  • The 65xx is not shown as such but 'absorbed' by the 64+xx handtype. This is OK if the 6 card suit is a major (best paid suit..). This is not good if the second suit is a major : we might miss a game contract in major not knowing that the second suit in the 64xx was a 5card. Therefore, when holding a 65xx with a major suit as 2nd suit : sell this hand as a 55xx

 

 

P

O

P

meaning

O

P

meaning

O

P

O

1♥

JNB : ? M

s12

s34

s56

♠/♥ in a 54xx

♠/♥ in a 64+xx

♠/♥ in a 6331

JNB : ? 2nd suit or sn

s123

s123

s123

2nd suit - RSC

2nd suit - RSC

sn - RSC

JNB :? sn

s12 (RSC)

JNB : ? $

1♠

JNB : ? m

s12

s34

s56

♦/♣ in a 54xx

♦/♣ in a 64+xx

♦/♣ in a 6331

JNB : ? 2nd suit or sn

s123

s123

s123

2nd suit - RSC

2nd suit - RSC

sn - RSC

JNB :? sn

s12 (RSC)

JNB : ? $

1NT

JNB : ? 5c

s1234

3x

5c - suit ( RSC)

7c in x

JNB :? id of dbt

or: ?$

s123

s123...

RSC

out of 8-10/11-12/...

JNB : ? $

 

 

2♣

s1:? #c in ♠

s2:? #c in ♥

s3:? #c in

s4:? #c in ♣

s5: ? $

 

s1234

 

s123....

 

# out of '2341

 

out of 8-10/11-12/...'

 

JNB :? #c in next suit

 

natural

s1234

# out of 4321

JNB : ? $

 

 

2

JNB : ? M

s12

6c ♠/♥

JNB : ? id of 3c

s123

suit of the 3card - RSC

JNB : ? $

 

 

2♥

JNB : ? m

s12

6c ♦/♣

JNB : ? id of 3c

s123

suit of the 3card - RSC

JNB : ? $

 

 

2♠

JNB (2NT)

s123

2nd suit (RSC)

JNB : ? $

s123...

out of 8-10/11-12/...

 

 

 

2NT

JNB (3♣ )

s123

♦/♥♣/♦ ♣

JNB : ? $

s123...

out of 8-10/11-12/...

 

 

 

3x

 

 

 

 

 

 

 

 

 

Comments

  • after a 2♣ first answer (no 5card) the opener can ask for the number of cards in a given suit. This suit is told via steps in RSC : s1=♠, s2=♥, s3=♦ , s4=♣ . The answer in given with steps refering to '2341' ( s1=2, s2=3, s3=4 , s4=1) , putting the number with highest probability first, in order to save bidding space. The following JNB of opener asks for the number of cards in the next RSC-suit. The answer to that question is according '4321' or '432' , again in order to keep the bids as low as possible.
  • the last JNB will be asking for strength even when partner is limited because of an initial pass.In that case opener wants to know min/max of this pass : s1=8-9hp s2=10-11 hp. After that , the game contract is made by the opener and if not, it is a controle bid.

Ask

#steps

 

1

4

ask for the id of the 1st suit of interest in a given promised hand type (id of major, minor, 5card, etc.)

2

3

ask for the id of the next suit of interest in the hand (2nd suit, doubleton, 3card..)

3

2

ask for the id of the suit with singleton, if any

4

4

ask for the strength of the hand

1st answer :

1

1

1NT

2

2

2

2

2NT

askings (A)

1-2-3-4

1-2-3-4

1-2-4

1-2-4

1-2-4

1-2-4

1-4

1-4

The extension technique (E.T.)

 

Usually, the opener asks and partners answers with steps.The asking happens with JNB. But when the answer is the last element of the reference sequence , we agree that partner can step beyond this "last" step and by doing so, addresses already the answer to the agreed next question. Examples will clarify :

 

O P

1♣ - 1♥ P promises a 54xx or 64+xx or 6331 with a major

1♠ - 2♣ P clarifies that ♥ is the major suit (step 2) in a 54xx handtype

2♦ - 3♣ O wants to know the 2nd ssuit by JNB 2♦ . P bids step 4 while there are only 3 remaining suits. So the 2nd suit is ♣ (step 3). But ♣ is the last element of the suit-sequence, therefor we can give AT THE SAME TIME the answer to the next asking (sn?) : step 3=2NT would have shown ♣ and no sn, so 3♣ = step4 or step2 of the next answer = sn♠ . The hand therefore is 1♠5♥3♦4♣.

 

O P

1♣ - 1♥ P promises a 54xx or 64+xx or 6331 with a major

1♠ - 3♦ P gives step 8 while basicly there are in this fase only 6 steps. We know therefor that the major suit must be ♥ in a 6331 handtype and 3♦ is the 3th step in the remaining suit sequence to identify the sn in the 6331: ♣ . In other words , the 3♦ answer reveals in one bid the complete hand : 3♠6♥3♦1♣

 

O P

1♣ - 2♣ P promises a 4333, 4432 or 4441 hand

2♦ - 3♦ O asks for he number of spades. P gives step 5 while basicly there are in this fase only 4 steps. We know therefor the hand has a sn spades AND at the same time that the strength is 11-12 hp.

 

O P

1♣ - 2♣ P promises a 4333, 4432 or 4441 hand

2♦ - 2♠ O asks for he number of spades. P gives step 2 = 3 card spades.

2♥ - 3♦ O asks for he number of hearts. The reference now is '432' because a sn has now become impossible.3♦ is step 4, whch means the last element of the reference(=2) AND a strength of 11-12hp. Therefore, the hand of P is 3♠2♥4♦4♣. If O continues with 3♥ then this a control bid, inviting P to do the same until the first game bid in a suit (4♥).

 

 

 

1 - 1♦ - ?

 

This complex is often active as the natural tendency is that the 52 cards are in balance, meaning that often a strong opener will meet a weak partner. The 1♦ answer means 0-7 hp or < 20 zps. The opener has following options :

O

Meaning

P

Meaning

O

1 ♥

20+, unbalanced.

1♠

4-7hp, MF,no 5card

natural

 

 

1NT

0-3hp

natural

 

 

2x

4-7hp,MF, 5 card

natural

1♠

16-19,5+c ♠

pass or natural bid

 

when 6-7hp

 

 

1NT

16-19hp

pass

 

 

 

 

2

puppet stayman

6-7hp

...

2x

16-19hp, 5c in x

pass or natural bid

 

when 6-7hp

 

 

 

 

 

 

When opponents overcall 1

 

  • when the overcall is double, 1 or 1 : system on (we ignore the overcall)
  • when the overcall is beyond 1 : system off (we continue in a natural way)

 

When system on, we get 2 extra bid-options : (re)double , pass .

When the overcall takes our (undisturbed) answer, we double :

eg. 1♣-(1♥)- X = "8+hp, 54xx w/ 5c M"

1♣-(1♦)- X = "6-7hp"

1♣-(1♦)- pass = "0-5hp"

 

When the auction is GF, and opponents intervene, the steps become :

s1=pass, s2=double, step 3= JNB, step 4 = JNB+1.

We call this approach : the PD12

 

When system off, the partner can show a balanced hand (no 5card,8+hp) with "double". The opener can now ask for the number of cards in a given suit via PD12.

 

If the opener asks for the number of cards in the suit of the opponent, this question is transformed into asking for a stop in that suit. Partner will bid NT with stop, and without a stop he will tell his strength in steps where the NT-step is skipped.