♠ ♥ ♦ ♣
N
W E
S
N/
♠ AK987
♥ QJ
♦ A4
♣ KJ53
♠ J2
♥ A1062
♦ KQ62
♣A102
♠ Q4
♥ K987
♦ 86
♣ Q9876
♠ 10653
♥ 543
♦ J9753
♣4
1.
♠ 6432
♥ K543
♦ J1097
♣ Q
♠ AQ5
♥ QJ106
♦ Q32
♣J63
♠ J10987
♥ A976
♦ 6
♣ K54
N
W E
S
♠ K9
♥ 8
♦ AK84
♣ A109872
2.
E/NZ
3.
♠ AJ2
♥ KQ2
♦ QJ983
♣ A6
♠ Q10643
♥ J5
♦ K7
♣ K984
4.
♠ KQ975
♥ A6
♦ AJ9
♣ KJ7
♠ A2
♥ KJ10854
♦ 874
♣ Q4
N  S 
1♣  1♥ 
1♠  1NT 
2♣  2♠ 
2NT  3♣ 
3♦  3♥ 
4♠  p 
N  S 
1♣  2♦ 
2♥  2NT 
3♣  3♥ 
3♠  3NT 
4♥  p 
p 

UNDER CONSTRUCTION
N  E  S  W 
1♣  p  1♦  p 
2♠  p  2NT  p 
3NT  p  p  p 
The auction
N :18hp and 36zp, more than enough to open 1♣
S : 7hp, so answer is 1♦
W : 14hp, no 5 card : pass
N : shows his 5 card w/ 2♠. Not 1♠ because this would mean 20+. Now (s)he limits the hand till 19hp.
S wants to show that (s)he has a maximum of 67hp because game is still possible. (s)He bids 2NT, denying a fit in spades.
N : accepts the invitation and raises to 3NT.
Playing
As long as West does not lead diamonds the contract is made : eg. ♥ 2 for ♥J. Then ♣ K for ♣A. West switches to diamonds but is too late. S makes 3♠,1♥ , 1♦ and 4 ♣ .
N  E  S  W 
 1♣  p  2♣ 
p  2♠  p  3♣ 
p  3♦  p  3♠ 
p  4♣  p  4♥ 
p  4NT  p  5♦ 
p  6♣  p  p 
p 



21 nov 2015
Turnhout
The auction
E : very unbalanced and so count the zarponits : 35zp (with 14hp) , so E opens 1♣
S and N always pass
W : 11hp, balanced, so 2 ♣
E : is interested in clubs but first asks the amount of cards in diamonds with step 3 (=2♠ )
W : the answer is step 2 (3 ♣ 2341 ) for 3 cards
E :JNB = 3♦ asks for length of clubs
W : 3♠ =step 2 (4321) , for also 3 cards clubs
E : because 3NT would be an endbid , he asks about strength with 4♣
W :4♥ is step 2 meaning 1112hp
E : 4:NT asking for aces
W : 5♦ =1 or 4
E can not stop anymore at 5♣ and risks a 6♣
Playing
E was lucky when S led with ♠J . For ♠ K .E collected A and Q of spades and could discard ♥ 8. Then ♣J for ♣Q and ♣A. When E continus with ♣10 S took ♣K and played ♥A, trumped with ♣7. Then E played ♣2 to collect S's last trump. Arriving in W with ♣6 he now played ♥ Q , ♥ K, trump. Via ♦Q he got back in W to play ♥J and discard a diamond. E makes 3♠, 1♥ , 3♦ and 5 ♣ . Contract, thanks to a happy lead.
N : 33zp, 1♣
S : 23zp, GF, 54xx in major, so 1♥
N : asks which M?
S : step 1=1NT so spades is the 5 card
N : JNB= 2nd suit?
S : 2♠ =step 3 of remaining suits=♣ BUT because ♣ is the last of the remaining suits S must apply the extension technique and tell in the same answer about a possible singleton. Step 1 becomes step 0 and indicates a 5422.
N : JNB 2NT to ask for the strength
S : step1 = 3♣, 810hp
N : fits with spades. No need to investigate slem, therefore : 4♠, although 3NT is an alternative.
N : 11+18+6=35zp, 1♣
S : 26zp, GF, 6322 in major, so 2♦
N : 2♥ = asks which M?
S : step 2=2NT so hearts is the 6 card
N : JNB=3♣= 3card suit?
S : 3♥ =step 2 of remaining suits=♦ which is not the last of the remaining suits and therefore the extension technique is NOT applicable.
N : JNB= 3♠ to ask for the strength
S : step1 = 3NT, 810hp
N : fits with hearts. He knows that S has two doubletons. Slem is near. On the edge. N decides for 4♥