Answers - undisturbed

• Pass : to play

• 2♣ :    The DUKE-convention (see Strategy in menu). The opener is expected to bid 2♦. The weak partner with a 5 card ♦ will pass or bid his 5 card major 2M.  Having a two suiter with 10-11hp, he can show this via 2NT (both minors),    3♣/♦  (5c ♣/♦ and 5c♥ ) and 3♥/♠ (5c ♣/♦ and 5c♠ )

• 2♦ : RF, 10+, relay bid . Asking to describe further the hand of opener with the conventional sixpack-answer : s123/456 (min and no 5card,5c♣,5c♦) / (max and no 5card,5c♣,5c♦). Then the continuation is natural.

• 2♥/♠ : RF, 10+hp, 5c ♥/♠  (no Jacoby transfer !) . Note that - due to the openings conditions - opener has ALWAYS a 3-2 or 3-3 card in the majors. His reply now is again stepwise simple :

s12 = min w/ 2-3c support M

s34 = max w/ 2-3c support M

s56 =  max , 2c M   with 5c ♣/♦

• 2NT : NF, 10-11 hp,   

• 3♣/♦: NF, 10-11 hp,6+c  ♣/♦
• 3♥/♠ : NF, 8-9hp, 6+c ♥/♠

• 3NT/4♥/♠ : to play

The 1NT  opening forms together with the 1♦ opening a tandem to treat all hands  without a 5 card major.

It is worthwhile to notice that Stayman is not necessary as the opening never contains a 4 card major. Yet, it hinders the opponents who have to enter the auction on level 2, not without risk.

When  opponents overcall  1 NT ?

If the opening is doubled, we apply the HELVIC procedure : 

• 2x = two suiter in x and x+1
• pass = or 9+hp  or two suiter in shape suits. If RHO passes, the opener must redouble. Partner with9+hp will now pass and else bid the lowest suit of his shape suits.

• redouble = 5c in a suit to be named after pass by LHO and 2♣ bid by opener

If RHO does not pass, the opener may not bid anymore. The danger of a penalty double has disappeared.